12^2=x(20-x)

Solution for 12^2=x(20-x) equation:

12^2=x(20-x)

We move all terms to the left:

12^2-(x(20-x))=0

We add all the numbers together, and all the variables

-(x(-1x+20))+12^2=0

We add all the numbers together, and all the variables

-(x(-1x+20))+144=0


We calculate terms in parentheses: -(x(-1x+20)), so:

x(-1x+20)

We multiply parentheses

-1x^2+20x

Back to the equation:

-(-1x^2+20x)


We get rid of parentheses

1x^2-20x+144=0

We add all the numbers together, and all the variables

x^2-20x+144=0

a = 1; b = -20; c = +144;
Δ = b2-4ac
Δ = -202-4·1·144
Δ = -176
Delta is less than zero, so there is no solution for the equation